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Simplifying 5c + 20c2 + 20c3 = 0 Solving 5c + 20c2 + 20c3 = 0 Solving for variable 'c'. Factor out the Greatest Common Factor (GCF), '5c'. 5c(1 + 4c + 4c2) = 0 Factor a trinomial. 5c((1 + 2c)(1 + 2c)) = 0 Ignore the factor 5.Subproblem 1
Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0Subproblem 2
Set the factor '(1 + 2c)' equal to zero and attempt to solve: Simplifying 1 + 2c = 0 Solving 1 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2c = 0 + -1 2c = 0 + -1 Combine like terms: 0 + -1 = -1 2c = -1 Divide each side by '2'. c = -0.5 Simplifying c = -0.5Subproblem 3
Set the factor '(1 + 2c)' equal to zero and attempt to solve: Simplifying 1 + 2c = 0 Solving 1 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2c = 0 + -1 2c = 0 + -1 Combine like terms: 0 + -1 = -1 2c = -1 Divide each side by '2'. c = -0.5 Simplifying c = -0.5Solution
c = {0, -0.5, -0.5}
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